576-192x+12x^2=0

Solution for 576-192x+12x^2=0 equation:

576-192x+12x^2=0

a = 12; b = -192; c = +576;
Δ = b2-4ac
Δ = -1922-4·12·576
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-192)-96}{2*12}=\frac{96}{24}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-192)+96}{2*12}=\frac{288}{24}
=12
$